Determine the amount of heat required to vaporize 200 g of water at boiling point.

Determine the amount of heat required to vaporize 200 g of water at boiling point. If the specific heat of vaporization of water is 2260 kJ / kg.

Given: m (mass of water for vaporization) = 200 g (0.2 kg); taken water is at boiling point.

Reference values: according to the condition L (specific heat of vaporization of water) = 2260 kJ / kg (2260 * 10 ^ 3 J / kg).

The required amount of heat for vaporization of 200 grams of water is calculated by the formula: Q = L * m.

Calculation: Q = 2260 * 10 ^ 3 * 0.2 = 452 * 10 ^ 3 J (452 kJ).

Answer: You need 452 kJ of heat.