Determine the amount of heat required to vaporize 8 kg of ether taken at a temperature of 10 ° C.
July 31, 2021 | education|
Q = Q1 + Q2.
Q1 (heating the ether to vaporization) = С * m * (t2 – t1), where С is the specific heat capacity of the ether (tabular value С = 2350 J / (K * kg)), m is the mass of the ether (m = 8 kg), t2 is the temperature of vaporization of the ether (tabular value t2 = 35 ° С), t1 is the initial temperature of the ether (t1 = 10 ºС).
Q2 (vaporization of ether) = L * m, where L is the specific heat of vaporization of ether (tabular value L = 0.4 * 10 ^ 6 J / kg).
Q = 2350 * 8 * (35 – 10) + 0.4 * 10 ^ 6 * 8 = 3670000 J or 3.67 MJ.
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