Determine the amount of heat required to vaporize 8 kg of ether taken at a temperature of 10 degrees Celsius.

Given:
m = 8kg,
t1 = 10 ° С,
t2 = 35 ° С – boiling point of ether,
c = 2340J / (kg * deg) – specific heat of ether,
r = 355000J / kg – specific heat of vaporization of ether;
Find: Q -?
The required amount of heat is:
Q = Q1 + Q2,
Where
Q1 = m * c * (t2 – t1) – the amount of heat required to heat the ether to the boiling point;
Q2 = m * r – the amount of heat required to convert boiling ether into steam;
Q = m * c * (t2 – t1) + m * r;
Q = 8 * 2340 * 20 + 8 * 355000 = 3214400J = 3.21MJ.