Determine the amount of heat that is released during the formation of 0.5 mol of hydrogen sulfide ZnS
| May 8, 2021 | education
Determine the amount of heat that is released during the formation of 0.5 mol of hydrogen sulfide ZnS + 2HCl = ZnCl2 + H2S + 140kJ
Let’s write the reaction equation:
ZnS + 2HCl = ZnCl2 + H2S + 140kJ
According to the equation, when 1 mol of H2S is formed, 140 kJ is released
This means that when 0.5 mol is formed, 70 kJ will be released.
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