Determine the amount of hydrogen released by the interaction of 31.2 g

Determine the amount of hydrogen released by the interaction of 31.2 g of potassium with propanol. yield 78% compared to theoretically possible.

To solve the problem, we compose the equation:
2С3Н7ОН + 2K = H2 + 2C3H7OK – substitution reaction, hydrogen gas is released;
Let’s calculate the molar masses of substances:
M (K) = 39.1 g / mol;
M (H2) = 2 g / mol.
Determine the amount of mol of potassium, if the mass is known:
Y (K) = m / M = 31.2 / 39.1 = 0.798 mol.
Let’s make the proportion:
0.798 mol (K) – X mol (H2);
-2 mol – 1 mol from here, X mol (H2) = 0.798 * 1/2 = 0.395 mol.
Find the volume of hydrogen:
V (H2) = 0.395 * 22.4 = 8.848 HP (theoretical product yield).
We determine the practical yield of hydrogen: V (H2) = 0.78 * 8.848 = 6.9 liters.
Answer: the volume of hydrogen is 6.9 liters.