Determine the amount of hydrogen that is released when dissolving 13g. zinc in hydrochloric acid solution.

molecular equation
Zn + 2HCl = ZnCl2 + H2
can be solved by the proportion method
13 g = x l
65 g / mol = 22.4 L / mol
x = 13 * 22.4 / 65 = 4.48 l
V (H2) = 4.48 L



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