Determine the amount of iron oxide 3 required to obtain pure iron in the amount of 112 g by aluminothermy.

univerkov | January 17, 2021 | education

Given:
m (Fe) = 112 g
To find:
m (Fe2O3)
Decision:
Fe2O3 + 2Al = Al2O3 + 2Fe
n (Fe) = m / M = 112 g / 56 g / mol = 2 mol
n (Fe): n (Fe2O3) = 2: 1
n (Fe2O3) = 2 mol / 2 = 1 mol
m (Fe2O3) = n * M = 1 mol * 160 g / mol = 160 g
Answer: 160 g

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