Determine the amount of oxygen required to burn 25 liters of methane (CH4).

The methane combustion reaction is described by the following chemical equation:

CH4 + 3O2 = CO2 + 2H2O;

To burn 1 mole of methane, 3 moles of oxygen are required.

Let’s calculate the amount of methane available.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

N CH4 = 1 x 0.85 / 22.40 = 0.0379 mol;

The same volume of carbon dioxide will be released during a chemical reaction.

Let’s calculate its volume.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

V O2 = 0.0379 x 22.40 = 0.85 liters;