Determine the amount of oxygen required to burn 8 grams of magnesium (2Mg + O2 = 2MgO).

The magnesium combustion reaction is described by the following chemical equation:

Mg + ½ O2 = MgO;

To burn 1 mol of magnesium, 0.5 mol of oxygen is required.

Let’s calculate the amount of magnesium available.

M Mg = 24 grams / mol;

N Mg = 8/24 = 0.333 mol;

To oxidize such an amount of magnesium, 0.333 / 2 = 0.166 mol of oxygen is required.

Let’s calculate its volume.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

V O2 = 0.1666 x 22.40 = 3.733 liters;