Determine the amount of oxygen required to obtain 12g of magnesium oxide?

Metallic magnesium reacts intensely with oxygen. This reaction is described by the following equation:

Mg + ½ O2 = MgO;

In this reaction, 1 oxygen atom is added to 1 magnesium atom and 1 molecule of magnesium oxide is synthesized.

Let’s determine the chemical amount of magnesium oxide.

To do this, divide the available weight of magnesium oxide by the weight of 1 mole of this substance.

M MgO = 24 + 16 = 40 grams / mol; N MgO = 16/40 = 0.4 mol;

To burn this amount of magnesium, 2 times less chemical (molar) amount of oxygen is required.

Let’s calculate its weight.

To do this, we multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol; m O2 = 0.4 / 2 x 32 = 6.4 grams;