Determine the amount of substance contained in 26.88 liters of sulfur oxide (VI).

Sulfur oxide (VI), aka sulfur trioxide, sulfuric anhydride has a molecular formula SO3. Under n.u. colorless gas with a pungent odor. It enters into chemical interaction with water in any ratio with the formation of sulfuric acid.

Under normal conditions, one mole of any gas occupies the same volume. This volume is 22.4 liters. This constant is called Avogadro’s number (after the Italian scientist Amedeo Avogadro).

Thus, the amount of gas substance at normal conditions is is equal to the ratio of the volume of this gas to the Avogadro number:

N = V / VM

where N is the amount of substance;

V is the gas volume;

VM is the molar volume of the gas.

N (SO3) = V (SO3) / VM = 26.88 / 22.4 = 1.2 (mol)

Answer: the amount of sulfur (VI) oxide substance is 1.2 mol.