m (HCl) = 1.46 g
n (HCl) -?
V (HCl) -?
N (HCl) -?
1) Calculate the molar mass of HCl:
M (HCl) = Mr (HCl) = Ar (H) + Ar (Cl) = 1 + 35.5 = 36.5 g / mol;
2) Calculate the amount of HCl substance:
n (HCl) = m (HCl) / M (HCl) = 1.46 / 36.5 = 0.04 mol;
3) Calculate the volume of HCl:
V (HCl) = n (HCl) * Vm = 0.04 * 22.4 = 0.896 l;
4) Calculate the number of HCl molecules:
N (HCl) = n (HCl) * NA = 0.04 * 6.02 * 10 ^ 23 = 2.408 * 10 ^ 22.
Answer: The amount of HCl substance is 0.04 mol; volume – 0.896 l; the number of molecules is 2.408 * 10 ^ 22.
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