Determine the amperage in the electric kettle connected to a network with a voltage of 125 V
| August 6, 2021 | education
Determine the amperage in the electric kettle connected to a network with a voltage of 125 V, if the resistance of the filament is 50 Ohm.
Given: U (voltage in the network to which the electric kettle is connected) = 125 V; R (kettle filament resistance) = 50 ohms.
According to Ohm’s law for a section of the circuit, the current in the electric kettle will be equal to the ratio of the voltage in the network and the resistance of the filament: I = U / R.
Let’s make a calculation: I = 125/50 = 2.5 A.
Answer: The current in the electric kettle is 2.5 A.
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