Determine the Archimedean force acting on a bar, the dimensions of which are 2 * 3 ^ 10 cm, in water.

Given:

a = 2 centimeters = 0.02 meters – the length of the bar;

b = 3 centimeters = 0.03 meters – the width of the bar;

c = 10 centimeters = 0.1 meter – the height of the bar;

ro = 1000 kg / m3 (kilogram per cubic meter) is the density of pure water.

It is required to determine F (Newton) – the Archimedean force acting on the bar when it is immersed in water.

Assuming that the bar has the shape of a rectangular parallelepiped, we determine its volume:

V = a * b * c = 0.02 * 0.03 * 0.1 = 0.0006 * 0.1 = 0.00006 m3.

Then, to determine the Archimedean force, you must use the following formula:

F = ro * V * g, where g = 9.8 Newton / kilogram;

F = 1000 * 0.00006 * 9.8 = 0.06 * 9.8 = 0.59 Newton (the result was rounded to one hundredth).

Answer: an Archimedean force of 0.59 Newton acts on the bar.