Determine the Archimedean force acting on a body with a volume of 2000 cm3 immersed in kerosene.

Determine the Archimedean force acting on a body with a volume of 2000 cm3 immersed in kerosene. The density of kerosene is 800 kg / m3.

We translate the dimension cm³ into m³ – 2000 cm³ will mean 0.002 m³ (since 1 m³ contains 1,000,000 cm³) ³.

The buoyancy force acting on a body immersed in a liquid will be equal to the weight of the liquid displaced by it, or, in other words, the weight of the liquid that fills the volume occupied by the body immersed in the liquid.

Fout = Vρg, where V is the volume of the body, ρ is the density of the liquid, g is the acceleration of gravity.

In our case, Fout = 0.002 m³ * 800 kg / m³ * 9.8 m / s² = 1.6 * 9.8 kg * m / s² = 15.68 N.