Determine the Archimedean force acting on a cork lifebuoy with a volume of 20 dm3 if it is 1/4 submerged in water.

Data: V (volume of the cork lifebuoy) = 20 dm3 (0.02 m3); V1 (volume of a circle immersed in liquid) = V / 4.
Constants: ρ (density of the water with which the lifebuoy is submerged) = 1000 kg / m3; g (acceleration due to gravity) = 9.81 m / s2.
The force of Archimedes, which acts on the cork lifebuoy, is calculated by the formula: Fа = ρ * g * V1 = ρ * g * V / 4.
Calculation: Fa = 1000 * 9.81 * 0.02 / 4 = 49.05 N.
Answer: An Archimedes force of 49.05 N. acts on the cork lifebuoy.