Determine the atmospheric pressure (in Pascals) on the 4th floor of the school (at a height of 12m)

Determine the atmospheric pressure (in Pascals) on the 4th floor of the school (at a height of 12m), if the atmospheric pressure on the first floor is 760mm Hg.

With small rises, on average, for every 12 m, the pressure increases by 1 mm Hg.
Atmospheric pressure equal to the pressure of a column of mercury 760 mm is considered normal and equal to 101300 Pa.
Let’s make the proportion:
760 mm Hg = 101300 Pa
1 mm Hg = x Pa
Hence x = 101300 * 1/760 = 133 Pa.
As you rise, the pressure decreases.
Divide the height by 12, find how much the pressure of the mercury column has decreased at this height:
12/12 = 1 mm Hg
Mine pressure:
760-1 = 755 mm Hg
Let’s translate into SI system:
755 * 133 = 100415 Pa.
Answer: pressure 755 mm Hg. or 100415 Pa.