Determine the average force acting on the hunter’s shoulder when firing, if the time of movement

Determine the average force acting on the hunter’s shoulder when firing, if the time of movement of the shot in the barrel of the gun is 0.05 s, the mass of the shot is 40 g, and its velocity when flying out of the gun is 300 m / s.

Initial data: t (duration of movement of the shot in the barrel of the gun) = 0.05 s; m (fraction weight) = 40 g (0.04 kg); V (velocity of the shot when leaving the gun) = 300 m / s.

1) Determine the acceleration with which the shot moved in the barrel of the gun: V = a * t and a = V / t = 300 / 0.05 = 6000 N.

2) Let’s calculate the force that will act on the hunter’s shoulder: F = m * a = 0.04 * 6000 = 240 N.

Answer: When fired, a force of 240 N acted on the hunter’s shoulder.