# Determine the average kinetic energy of the translational motion of a gas molecule at a temperature of 150 degrees Celsius.

Given:
t = 150 degrees.
Find: E is kinetic.
Decision:
To solve the problem, we will use the formula for translational motion. It looks like this: Up = 3 / 2VRT.
Next, we write down the formula for the total number of molecules: N = VNa.
Next, we need to divide the kinetic energy by this formula and we will get a way to find potential energy. En = Ek / Na.
Let’s substitute other expressions into it and get: En = 3 / 2VRT: (VNa) = 3 / 2RT: Na = 3/2 R / Na * T = 3 / 2kT.
It is important not to forget that T in Kelvin will be expressed through T in Celsius, that is, T = t + 273K.
Then we get En = 3 / 2k (T + 273K).
Substitute the values ​​and calculate: En = 3/2 * 1.38 * 10 ^ -23 (-50 +273) = (3/2 * 1.38 * 10 ^ -23 * 223) = 4, 62 * 10 ^ – 21 J.
Answer: 4, 62 * 10 ^ -21

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