# Determine the average kinetic energy of the translational motion of a gas molecule at a temperature of 150 degrees Celsius.

Given:

t = 150 degrees.

Find: E is kinetic.

Decision:

To solve the problem, we will use the formula for translational motion. It looks like this: Up = 3 / 2VRT.

Next, we write down the formula for the total number of molecules: N = VNa.

Next, we need to divide the kinetic energy by this formula and we will get a way to find potential energy. En = Ek / Na.

Let’s substitute other expressions into it and get: En = 3 / 2VRT: (VNa) = 3 / 2RT: Na = 3/2 R / Na * T = 3 / 2kT.

It is important not to forget that T in Kelvin will be expressed through T in Celsius, that is, T = t + 273K.

Then we get En = 3 / 2k (T + 273K).

Substitute the values and calculate: En = 3/2 * 1.38 * 10 ^ -23 (-50 +273) = (3/2 * 1.38 * 10 ^ -23 * 223) = 4, 62 * 10 ^ – 21 J.

Answer: 4, 62 * 10 ^ -21