Determine the buoyancy for a 3 x 2 x 4 cm plug.

The buoyant force is the force of Archimedes
Farch = рgV, where p is the density of the liquid, V is the volume of the submerged part of the body, g is the acceleration of gravity.
We will assume that the cork is in the water
3x2x4 cm = 0.03×0.02×0.04 m
Three dimensions – volume
V = 0.03 * 0.02 * 0.04 = 0.000024 m3
p = 1000 kg / m3
Farch = 0.000024 m3 * 1000 kg / m3 * 10 N / kg = 0.24 N
Answer: 0.24 N = Fapx