Determine the buoyant force acting on a body with a volume of 0.03 m3 if it is immersed in oil p = 800 kg / m3

V = 0.03 m ^ 3.
ρ = 800 kg / m ^ 3.
g = 9.8 m / s ^ 2.
Farkh -?
According to Archimedes’ law, Farch = ρ * g * V, where ρ is the density of the fluid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed body.
Farch = 800 kg / m ^ 3 * 9.8 m / s ^ 2 * 0.03 m ^ 3 = 235.2 N.
Answer: a buoyant force Farch = 235.2 N acts on the body