Determine the capacitance of the circuit, the inductance of which is 1 μH, if it emits electromagnetic waves 60 m long.

These tasks: L (inductance of the taken circuit) = 1 μH (1 * 10 ^ -6 H); λ (length of electromagnetic waves) = 60 m.

Reference values: υ (speed of electromagnetic waves) = 3 * 10 ^ 8 m / s.

The capacity of the contour taken can be expressed from the following equality: λ / υ = Т = 2 * Π * √ (L * C), whence √ (L * C) = λ / (υ * 2 * Π) and C = λ ^ 2 / (υ ^ 2 * 4 * Π ^ 2 * L).

Let’s perform the calculation: C = 60 ^ 2 / ((3 * 10 ^ 8) ^ 2 * 4 * 3.14 ^ 2 * 1 * 10 ^ -6) = 1 * 10 ^ -9 Ф = 1 nF.

Answer: The capacitance of the circuit taken is 1 nF.