Determine the capacity of the vessel if the mass of the empty vessel is 600 grams and 2 kg filled with kerosene?

Subtracting from the mass mpl = 2 kg of the vessel filled with kerosene, the mass mps = 600 g of the empty vessel, we determine the mass mk of kerosene in the vessel (in this case, we use the equality 1 kg = 1000 g). We have: mk = mpl – mps = 2 kg – 600 g = 2 kg – (600: 1000) kg = (2 – 0.6) kg = 1.4 kg. The density of kerosene (see from the table) ρ = 800 kg / m³. Using the formula V = m / ρ, where V is the volume of a homogeneous body (in m³), m is its mass (in kg), ρ is its density (in kg / m³), we calculate: V = m / ρ = (1, 4 kg) / (800 kg / m³) = (1.4: 800) m³ = 0.00175 m³ = (0.00175 * 1000) dm³ = 1.75 cm³ = 1.75 liters.