Determine the capacity of the vessel if the weight of the empty vessel is 600 g, and the weight of the one filled with kerosene is 2 kg.

Given: m1 (the mass of the vessel when kerosene was poured into it) = 2 kg; m2 (empty weight of the vessel) = 600 g (0.6 kg).

Constant values: ρк (tabular value of kerosene density) = 800 kg / m3.

The capacity of the vessel is determined from the formula for calculating the volume: V = m / ρк = (m1 – m2) / ρк.

Let’s make the calculation: V = (2 – 0.6) / 800 = 1.4 / 800 = 0.00175 m3 (1.75 dm3 or 1750 cm3).

Answer: The capacity of this vessel is 0.00175 m3.