Determine the change in impulse of a body weighing 3 kg in 5 seconds under the action of a force of 20N

m = 3 kg.

t = 5 s.

F = 20 N.

Δp -?

The momentum of a body p is a vector physical quantity equal to the product of the body’s mass m by its speed of motion V: p = m * V.

Since the body mass m does not change during movement, the change in impulse Δp is expressed by the formula: Δp = m * ΔV.

Let’s write 2 Newton’s law: a = F / m.

We express the acceleration a by the formula: a = ΔV / t.

ΔV / t = F / m.

m * ΔV = F * t.

Δp = F * t.

Δp = 20 N * 5 s = 100 kg * m / s.

Answer: the momentum of the body under the action of the force will change by Δp = 100 kg * m / s.