Determine the change in the impulse of a vehicle weighing 2 tons, with an increase in speed from 36 to 54 km / h.

Given:
m = 2t = 2000kg
V1 = 36 km / h = 10 m / s
V2 = 54 km / h = 15 m / s
Find: Δp -?
Decision:
ΔV = V2 – V1 = 15 – 10 = 5 (m / s)
Δp = ΔV * m = 5 * 2000 = 10000 (kg * m / s)
Answer: 10000 kg * m / s.



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