Determine the charge of a 1000 microfarad capacitor at 50 volts. Find the energy of the electric field of the condenser.
| June 3, 2021 | education
Data: C (capacitance) = 1000 μF (1000 * 10 ^ -6 F); U (voltage) = 50 V.
1) Determine the charge of the capacitor at the given parameters: C = q / U, whence q = C * U = 1000 * 10 ^ -6 * 50 = 0.05 Cl.
2) Find the energy of the electric field of a given capacitor: Wc = 0.5 * C * U ^ 2 = 0.5 * 1000 * 10 ^ -6 * 50 ^ 2 = 1.25 J.
Answer: The charge of the capacitor is 0.05 C, the energy of the electric field is 1.25 J.
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