Determine the cross-sectional area and length of the copper conductor. resistance 0.2 ohm weight 0.2 ohm.

Given: R = 0.2 ohm; m = 0.2 kg.

Constants: ρm (density) = 8.9 * 10 ^ 3 kg / m3; ρ (specific electrical resistance) = 0.017 Ohm * mm2 / m (0.017 * 10 ^ -6 Ohm * m2 / m).

1) Volume of the conductor: V = m / ρm = 0.2 / (8.9 * 10 ^ 3) = 2.25 * 10 ^ -5 m3.

2) Sectional area: R = ρ * l / S = ρ * (V / S) / S = ρ * V / S2; S = √ (ρ * V / R) = √ (0.017 * 10 ^ -6 * 2.25 * 10 ^ -5 / 0.2) = 1.38 * 10 ^ -6 m2 = 1.38 mm2.

3) Conductor length: R = ρ * l / S = ρ * l / (V / l) = ρ * l ^ 2 / V; l = √ (R * V / ρ) = √ (0.2 * 2.25 * 10 ^ -5 / 0.017 * 10 ^ -6) = 16.27 m.