Determine the current density if 6 * 10 ^ 18 electrons have passed through a conductor with
| August 15, 2021 | education
Determine the current density if 6 * 10 ^ 18 electrons have passed through a conductor with a cross section of 1.22 mm ^ 2 in 0.4 s.
Task data: t (elapsed time) = 0.4 s; S (conductor section) = 1.22 mm2; n (number of electrons passed) = 6 * 10 ^ 18 electrons; qе – electron charge (qе = -1.6 * 10 ^ -19 C).
Current density: ρ = I / S = (q / t) / S = n * qе / (t * S) = 6 * 10 ^ 18 * 1.6 * 10 ^ -19 / (0.4 * 1.22 ) = 1.967 A / mm2.
Answer: The current density is 1.967 A / mm2.
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