Determine the current density if, in 0.4 s, 6 * 10 ^ 18 electrons have passed through a conductor whose

Determine the current density if, in 0.4 s, 6 * 10 ^ 18 electrons have passed through a conductor whose cross-sectional area is 1.2 mm ^ 2.

Data: t (duration of movement of electrons through the conductor) = 0.4 s; S (cross-section of the conductor used) = 1.2 mm2 (in SI S = 1.2 * 10 ^ -6 m2); N (number of electrons) = 6 * 10 ^ 18 electrons.

Reference values: e (electron charge) = -1.6 * 10 ^ -19 Cl.

The current density in the conductor used is calculated by the formula: j = I / S = q / (S * t) = N * e / (S * t).

Let’s make a calculation: j = 6 * 10 ^ 18 * 1.6 * 10 ^ -19 / (1.2 * 10 ^ -6 * 0.4) = 2 * 10 ^ 6 A / m2.

Answer: The current density is 2 * 10 ^ 6 A / m2.