Determine the current flowing through a graphite rod 40 cm long and 2 mm in radius
| September 9, 2021 | education
Determine the current flowing through a graphite rod 40 cm long and 2 mm in radius at a voltage of 12 V. The resistivity of the graphite rod.
Data: l (graphite rod length) = 40 cm = 0.4 m; R (rod radius) = 2 mm; U (effective voltage) = 12 V; ρg (specific electrical resistance of graphite) = 400 Ohm * mm2 / m.
The current strength in the indicated graphite rod is applied by the formula: I = U / R = U / (ρg * l / S) = U * Π * R ^ 2 / (ρg * l) = 12 * 3.14 * 2 ^ 2 / ( 400 * 0.4) = 0.942 A.
Answer: The current passing through the indicated graphite rod is 0.942 A.
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