Determine the current in the conductor if it attracts a parallel conductor 2.8 m long with a current

| April 11, 2021 | education

Determine the current in the conductor if it attracts a parallel conductor 2.8 m long with a current of 58 A with a force of 3.4×10 ^ -3 N. How are the currents in both conductors directed? Distance between conductors 0.12 m.

Given: l (length of parallel conductor) = 2.8 m; I2 (current in parallel. Conductor) = 58 A; Fa (force of attraction of conductors) = 3.4 * 10 ^ -3 N; R (distance between conductors) = 0.12 m.

Constants: k (proportional coefficient) = 2 * 10 ^ -7 N / A ^ 2.

The current strength in the first conductor is determined by the formula: Fa = k * I1 * I ^ 2 * l / R, whence I1 = Fa * R / (k * I ^ 2 * l).

Let’s make a calculation: I1 = 3.4 * 10 ^ -3 * 0.12 / (2 * 10 ^ -7 * 58 * 2.8) = 12.56 A.

Because conductors attract, then electric currents flow in one direction.



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