Determine the current strength in an aluminum wire 10 cm long and a cross-sectional area of 1 mm ^ 2.

Determine the current strength in an aluminum wire 10 cm long and a cross-sectional area of 1 mm ^ 2. if the voltage on it is 2.8V.

S = 1 mm2 = 1 * 10-6 mm2,
U = 2.8 V.
ρ = 2.8 * 10-8 Ohm * m.
I -?
I = U / R – Ohm’s law for the circuit section.
We express the resistance of an aluminum conductor by the formula: R = ρ * l / S, where ρ is the resistivity of aluminum, l is the length of the conductor, S is its cross-sectional area.
The current strength in the aluminum conductor I will be determined by the formula: I = U * S / ρ * l.
I = 2.8 V * 1 * 10-6 mm2 / 2.8 * 10-8 Ohm * m * 0.1 m = 1000 V = 1 kV.
Answer: in an aluminum conductor, the current strength is I = 1 kV.