Determine the current strength passing through an aluminum conductor with a length of l = 1.5 v

Determine the current strength passing through an aluminum conductor with a length of l = 1.5 v and an area of cross-section S = 0.20 mm square voltage across it Y = 0.30 V.

According to Ohm’s law, the current in an aluminum conductor will be directly proportional to the effective voltage and inversely proportional to the resistance of the conductor.

I = U / R, where U is the voltage (U = 0.3 V), R is the resistance (R = ρ * l / S, where ρ is the resistivity of aluminum (ρ = 0.027 Ohm * mm² / m), l – conductor length (l = 1.5 m), S – cross-sectional area (S = 0.2 mm2)).

I = U / (ρ * l / S) = U * S / (ρ * l) = 0.3 * 0.2 / (0.027 * 1.5) = 1.48 A.

Answer: The current is 1.48 A.