Determine the density of the liquid that is pressing 700 kPa at the bottom of the cavity.

Determine the density of the liquid that is pressing 700 kPa at the bottom of the cavity. The depth of the depression is 70 meters. Write down which liquids.

Given: p = 700kPa, h = 70m, P (density) =?
g = 10H
SI: 700kPa = 700000Pa
Solution: p = Pgh, P = p: (gh)
P = 700000: (10 * 70) = 700000: 700 = 1000kg / m3
Answer: 1000kg / m3 is P (density) of water



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