Determine the depth of water in the tank at which the absolute pressure is 140 kPa.

Given:

P = 140 kPa = 140 * 10 ^ 3 Pascal – absolute pressure at a certain depth in a reservoir with water;

Pa = 101 kPa = 101 * 10 ^ 3 Pascal – atmospheric pressure;

ro = 1000 kg / m ^ 3 – water density;

g = 9.8 m / s ^ 2 – acceleration of gravity.

It is required to determine the depth of the tank h (meter).

Let’s find the excess pressure created by the water column:

P1 = P – Pa = 140 * 10 ^ 3 – 101 * 10 ^ 3 = 39 * 10 ^ 3 Pascal.

Then the depth of the tank will be equal to:

h = P1 / (ro * g) = 39 * 10 ^ 3 / (1000 * 9.8) = 39 / 9.8 = 3.98 meters.

Answer: The depth of the tank is 3.98 meters (approximately 4 meters).