Determine the dielectric constant of a substance in which at a distance of r = 0.12 m. From each other there

Determine the dielectric constant of a substance in which at a distance of r = 0.12 m. From each other there are two point charges q1 = 8nC and q2 = 16nC, if the modulus of the force of their electrostatic interaction is F = 20μN

Given: r (distance between point charges) = 0.12 m; q1 (first charge) = 8 nC (8 * 10 ^ -9 C); q2 (second charge) = 16 nC (16 * 10 ^ -9 C); F (modulus of force of electrostatic interaction) = 20 μN (20 * 10 ^ -6 N).

Constants: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

We express the dielectric constant of a substance from the Coulomb law: F = k * q1 * q2 / (ε * r ^ 2), whence ε = k * q1 * q2 / (F * r ^ 2).

Let’s calculate: ε = 9 * 10 ^ 9 * 8 * 10 ^ -9 * 16 * 10 ^ -9 / (20 * 10 ^ -6 * 0.12 ^ 2) = 4.