Determine the distance traveled by the boat if it will move for 10 s at a constant speed of 5 m / s

Determine the distance traveled by the boat if it will move for 10 s at a constant speed of 5 m / s, and then for 10 s at a constant acceleration of 0.5 m / s2.

t1 = 10 s.

V1 = 5 m / s.

t2 = 10 s.

a = 0.5 m / s ^ 2.

S -?

The entire path of the boat S will be the sum of the path of the boat with uniform motion S1 and the path of the boat with uniformly accelerated motion S2: S = S1 + S2.

The traversed path S1 with uniform movement is determined by the formula: S1 = V1 * t1, where V1 is the speed of uniform movement, t1 is the time of uniform movement.

The traversed path S2 with uniformly accelerated movement is determined by the formula: S2 = V1 * t2 + a * t2 ^ 2/2, where V1 is the initial speed of movement, t2 is the time of uniformly accelerated movement, a is acceleration.

S = V1 * t1 + V1 * t2 + a * t2 ^ 2/2.

S = 5 m / s * 10 s + 5 m / s * 10 s + 0.5 m / s ^ 2 * (10 s) ^ 2/2 = 125 m.

Answer: the boat covered the path S = 125 m.