Determine the efficiency of a heat engine with a heater temperature of 200g and a refrigerator temperature of 10g.

univerkov | July 9, 2021 | education

Data: Тн (heater temperature) = 200 ºС = 473 К; Tkhol (refrigerator temperature) = 10 ºС = 283 K.
To determine the efficiency of the specified heat engine, we will use the formula: η = (1 – Тhol / Тн) = (1 – 283/473) = 0.402 or 40.2%.
Answer: The efficiency of this heat engine is 40.2%.

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