Determine the efficiency of an ideal heat engine with a heater temperature of 480 ° C, a refrigerator temperature of 30 ° C.
| August 31, 2021 | education
Data: Tn (heater temperature of an ideal heat engine) = 480 ºС (absolute temperature 753 K (480 ºС + 273 K)); Tx (temperature of the refrigerator of an ideal heat engine) = 30 ºС (absolute temperature 303 K (30 ºС + 273 K)).
The efficiency can be determined by the formula: η = (Тн – Тх) / Тн.
Calculation: η = (753 – 303) / 753 = 450/753 = 0.5976 (59.76%).
Answer: The efficiency of an ideal heat engine with the given parameters is 59.76%.
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