Determine the efficiency of the heat engine, which receives 100 J of heat from the heater per cycle

Determine the efficiency of the heat engine, which receives 100 J of heat from the heater per cycle and gives the refrigerator 80 J of heat

Given: Q1 (heat received by the heater during the cycle) = 100 J; Q2 (heat that the heater gave to the refrigerator during the cycle) = 80 J.

The efficiency of a heat engine is calculated by the formula: η = ((Q1 – Q2) / Q1) * 100%.

Let’s calculate the efficiency: η = ((100 – 80) / 100) * 100% = 0.2 * 100% = 20%.

Answer: According to the calculation, the heat engine has an efficiency of 20%.