# Determine the efficiency of the inclined plane, if a body weighing 150 kg was lifted along the inclined plane

August 29, 2021 | education

| **Determine the efficiency of the inclined plane, if a body weighing 150 kg was lifted along the inclined plane to a height of 1.5 m, acting with a force of 900 N. The length of the inclined plane is 4 m.**

To calculate the efficiency of a given inclined plane, we apply the formula: η = Ap / Az = m * g * h / (F * l).

Constants and variables: m is the mass of the lifted body (m = 150 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – lifting height (h = 1.5 m); F is the acting force (F = 900 N); l is the length of the plane (l = 4 m).

Let’s perform the calculation: η = m * g * h / (F * l) = 150 * 10 * 1.5 / (900 * 4) = 0.625 or 62.5%.

Answer: The efficiency of the plane is 62.5%.

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