Determine the efficiency of the tractor engine, which required 1.5 kg
| May 29, 2021 | education
Determine the efficiency of the tractor engine, which required 1.5 kg of fuel with a specific calorific value of 4.2 × J / kg to perform work of 1.89 × J.
Given:
A = 1.89 J;
m = 1.5 kg;
q = 4.2 J / kg;
Efficiency -?
Decision:
Efficiency = A / Q * 100%, Q = q * m;
Q = 1.5 * 4.2 = 6.3 J;
Efficiency = 1.89 / 6.3 * 100% = 30%.
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