Determine the elastic force arising in the spring if its deformation is 20 cm and the cruelty is 10 N / m.
| March 30, 2021 | education
x = 20 cm = 0.2 m.
k = 10 N / m.
Fupr -?
Hooke’s law: the elastic force Fcont, which arises during deformation of the body, is directly proportional to the change in the length of the body x and directed in the opposite direction to the change: Fcont = – k * x.
k – coefficient of proportionality, which is called the rigidity of the body.
The sign “-” shows that the elastic force Ffr counteracts the change in the length of the body.
If the body increases in length, it is stretched, then the elastic force tries to prevent this from happening.
Fcont = 10 N / m * 0.2 m = 2 N.
Answer: an elastic force Fel = 2 N. appeared in the spring.
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