Determine the elongation of the spring if a force of 10N acts on it. spring rate 500N / m.

Data: F (the amount of force that acts on the spring) = 10 N; k (rigidity of the taken spring) = 500 N / m.
The elongation of the taken spring can be determined using Hooke’s law: F = -Ftr = k * Δl, whence Δl = F / k.
Let’s make the calculation: Δl = 10/500 = 0.02 m.
Answer: The calculated value of the spring elongation is 0.02 m.



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