Determine the force acting on the charge 1.6 nC in an electric field with a strength of 50 kV / m.

Given:
q = 1.6 nC
E = 50 kV / m
Find: F =?
Decision:
To solve the problem, it is necessary to translate into SI units.
q = 1.6 nC = 1.6 × 10 ^ (- 9)
E = 50 kV / m = 5 × 10 ^ 4 V / m
F = q × E
F = 1.6 × 10 ^ (- 9) × 5 × 10 ^ 4 = 8 × 10 ^ (- 5) H
Answer: F = 8 × 10 ^ (- 5) H



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