Determine the force of air pressure on a palm with an area of 45 cm at an atmospheric pressure of 760 mm Hg. Art.

S = 45 cm ^ 2 = 0.0045 m ^ 2.
P = 760 mm Hg. Art. = 101080 Pa.
F -?
1 m ^ 2 = 10000 cm ^ 2, 45 cm ^ 2 = 0.0045 m ^ 2.
Pressure 1 mm Hg. st = 133 Pa, 760 mm Hg. Art. = 760 mm Hg. Art. * 133 = 101080 Pa.
P = F / S, pressure P is the ratio of the force F to the area S on which this force acts.
F = P * S.
F = 101080 Pa * 0.0045 m ^ 2 = 454.86 N.
Answer: force F = 454.86 N. acts on the palm.