Determine the force of gravity of the cable with a vertical tension of the cable with a vertical

Determine the force of gravity of the cable with a vertical tension of the cable with a vertical lift of a load weighing 200 kg with an acceleration of 2.5 m / s2

m = 200 kg.
g = 9.8 m / s2.

a = 2.5 m / s2.

N -?

m * a = N – m * g – 2 Newton’s law.

N = m * a + m * g = m * (a + g).

N = 200 kg * (2.5 m / s2 + 9.8 m / s2) = 2460 N.

Answer: the tension force of the cable when lifting the body is N = 2460 N.



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