Determine the force of gravity of the cable with a vertical tension of the cable with a vertical
September 30, 2021 | education
| Determine the force of gravity of the cable with a vertical tension of the cable with a vertical lift of a load weighing 200 kg with an acceleration of 2.5 m / s2
m = 200 kg.
g = 9.8 m / s2.
a = 2.5 m / s2.
N -?
m * a = N – m * g – 2 Newton’s law.
N = m * a + m * g = m * (a + g).
N = 200 kg * (2.5 m / s2 + 9.8 m / s2) = 2460 N.
Answer: the tension force of the cable when lifting the body is N = 2460 N.
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