Determine the force of pressure of gasoline on the bottom of the tank, with an area of 250 cm

Determine the force of pressure of gasoline on the bottom of the tank, with an area of 250 cm squared, if the tank is filled to a height of 18 cm, and the density of gasoline is 710 kg / m3.

Given: S (bottom area) = 250 cm2 (in SI S = 250 * 10-4 m2); h (the height of the column of gasoline in the tank) = 18 cm (in SI h = 0.18 m).

Constants: g (acceleration due to gravity) ≈ 10 m / s2; according to the condition ρb (gasoline density) = 710 kg / m3.

To determine the force of gasoline pressure at the bottom of the taken tank, we use the equality: F / S = P = ρb * g * h, whence F = ρb * g * h * S.

Let’s calculate: F = 710 * 10 * 0.18 * 250 * 10-4 = 31.95 N.

Answer: Gasoline presses on the bottom of the taken tank with a force of 31.95 N.