Determine the force of pressure of passengers on the floor of the elevator car if their weight is 150 kg

Determine the force of pressure of passengers on the floor of the elevator car if their weight is 150 kg with uniform movement.

These tasks: m (the mass of all passengers in the elevator) = 150 kg; the movement of the considered elevator is uniform (a = 0 m / s2).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

Since the lift moves uniformly, the desired pressure of passengers on the floor of the cabin is equal to their weight: m * a = 0 = Ft – N = Ft – P, whence P = Ft = m * g.

Calculation: P = 150 * 10 = 1.5 * 10 ^ 3 N (1.5 kN).

Answer: All passengers press on the floor of the elevator car with a force of 1.5 kN.